Integrand size = 15, antiderivative size = 35 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=-\frac {1}{2 a x^2}-\frac {b \log (x)}{a^2}+\frac {b \log \left (a+b x^2\right )}{2 a^2} \]
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Time = 0.02 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {1598, 272, 46} \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=\frac {b \log \left (a+b x^2\right )}{2 a^2}-\frac {b \log (x)}{a^2}-\frac {1}{2 a x^2} \]
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Rule 46
Rule 272
Rule 1598
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{x^3 \left (a+b x^2\right )} \, dx \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {1}{x^2 (a+b x)} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (\frac {1}{a x^2}-\frac {b}{a^2 x}+\frac {b^2}{a^2 (a+b x)}\right ) \, dx,x,x^2\right ) \\ & = -\frac {1}{2 a x^2}-\frac {b \log (x)}{a^2}+\frac {b \log \left (a+b x^2\right )}{2 a^2} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=-\frac {1}{2 a x^2}-\frac {b \log (x)}{a^2}+\frac {b \log \left (a+b x^2\right )}{2 a^2} \]
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Time = 2.06 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.91
method | result | size |
default | \(-\frac {1}{2 a \,x^{2}}-\frac {b \ln \left (x \right )}{a^{2}}+\frac {b \ln \left (b \,x^{2}+a \right )}{2 a^{2}}\) | \(32\) |
norman | \(-\frac {1}{2 a \,x^{2}}-\frac {b \ln \left (x \right )}{a^{2}}+\frac {b \ln \left (b \,x^{2}+a \right )}{2 a^{2}}\) | \(32\) |
parallelrisch | \(-\frac {2 b \ln \left (x \right ) x^{2}-b \ln \left (b \,x^{2}+a \right ) x^{2}+a}{2 x^{2} a^{2}}\) | \(33\) |
risch | \(-\frac {1}{2 a \,x^{2}}-\frac {b \ln \left (x \right )}{a^{2}}+\frac {b \ln \left (-b \,x^{2}-a \right )}{2 a^{2}}\) | \(35\) |
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Time = 0.25 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.94 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=\frac {b x^{2} \log \left (b x^{2} + a\right ) - 2 \, b x^{2} \log \left (x\right ) - a}{2 \, a^{2} x^{2}} \]
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Time = 0.13 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=- \frac {1}{2 a x^{2}} - \frac {b \log {\left (x \right )}}{a^{2}} + \frac {b \log {\left (\frac {a}{b} + x^{2} \right )}}{2 a^{2}} \]
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Time = 0.20 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=\frac {b \log \left (b x^{2} + a\right )}{2 \, a^{2}} - \frac {b \log \left (x\right )}{a^{2}} - \frac {1}{2 \, a x^{2}} \]
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Time = 0.26 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.23 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=-\frac {b \log \left (x^{2}\right )}{2 \, a^{2}} + \frac {b \log \left ({\left | b x^{2} + a \right |}\right )}{2 \, a^{2}} + \frac {b x^{2} - a}{2 \, a^{2} x^{2}} \]
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Time = 10.66 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.89 \[ \int \frac {1}{x^2 \left (a x+b x^3\right )} \, dx=\frac {b\,\ln \left (b\,x^2+a\right )}{2\,a^2}-\frac {1}{2\,a\,x^2}-\frac {b\,\ln \left (x\right )}{a^2} \]
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